800=-6t^2+800

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Solution for 800=-6t^2+800 equation: 



800=-6t^2+800

We move all terms to the left:

800-(-6t^2+800)=0

We get rid of parentheses

6t^2-800+800=0

We add all the numbers together, and all the variables

6t^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{12}=0$

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